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Memento Mori
18th-November-2007, 02:09 AM
http://img265.imageshack.us/img265/2199/sendmoremoneyyd5.jpg

Rules

1. Every letter stands for a digit between 0 and 9.
2. No two letters can represent the same digit.

Objective

Work out what all the letters stand for.
fatuma
18th-November-2007, 02:22 AM
not very hard to figure out

we did this as training in school.....before looooooooooooong time :p
Big!
18th-November-2007, 02:23 AM
Is D < E < M < N < O < R < S < Y? Also, is it safe to assume that this is setup as a math problem? If so, is it + - / or *?
Memento Mori
18th-November-2007, 02:23 AM
It is a maths problem. You don't need me to tell you the operator though. And your order is also incorrect.
Big!
18th-November-2007, 02:27 AM
It has to be + or * unless M is 0.
Memento Mori
18th-November-2007, 02:29 AM
There's only one it can be.
Big!
18th-November-2007, 02:31 AM
Can't be multiplication, because two 4 digit numbers don't multiply to a five digit number. Can't be division because a 4 digit number divided by a 4 digit number is not a 5 digit number. and xxxx/xxx != xxxx if m is 0.

Also can't be subtraction, therefore it must be addition.

M can't be 0
Memento Mori
18th-November-2007, 02:33 AM
Bingo. Now you have to start working out the numbers. The fact that you now know it is an addition should help you.

M has to be 0

Wrong, I'm afraid.
Big!
18th-November-2007, 02:43 AM
Yeah M != 0, E != 0, M must be 1
Memento Mori
18th-November-2007, 02:50 AM
M = 1. This is because 9999+9999 = 19998. 9999 is the maximum value of any 4-digit number, and hence 1 is the maximum value a fifth can take if you add two 4-digit numbers together.
Big!
18th-November-2007, 03:06 AM
SEND => 9567
+
MORE => 1085
=
MONEY => 10652

D=7, Y=2, E=5, N=6, R=8, M=1, S=9, O=0

Took me a minute, but I figured it out.

Big!
Memento Mori
18th-November-2007, 03:13 AM
Congratulations. That is correct.
Big!
18th-November-2007, 03:14 AM
The N and the E were tricky, until I recognized the carry can never be more than 1.

Big!
Memento Mori
18th-November-2007, 03:22 AM
Yeah. E + 0 != N, so there has to be a carry.
Big!
18th-November-2007, 03:28 AM
I thought the binary and signed binary addition I do in my Logic Design class was tricky, that's child's play compared to this problem. :)

Big!
kip0130
18th-November-2007, 04:38 AM
im totally confused.
Memento Mori
18th-November-2007, 12:39 PM
Not a mathmatician?
kip0130
18th-November-2007, 03:13 PM
Not a mathmatician?
not really.
imported_James
19th-November-2007, 09:21 AM
lol i found the solution!
Memento Mori
19th-November-2007, 09:30 AM
Was it a few posts above?
imported_James
19th-November-2007, 09:33 AM
oh my bad i didn't see the second page lol, no i actually typed it into yahoo... X_X
Memento Mori
19th-November-2007, 09:52 AM
Didn't bother trying to work it out then?
kaje
19th-November-2007, 10:43 AM
basically the M has to be a lower number than S seeing as M is the final product. Thus meaning M will be 1 or 2, and S will be 8 or 9. I will have the solution in a moment.
kaje
19th-November-2007, 10:46 AM
9567+
1085
------
10652

Woops, didn;t see the second page - edit!
Memento Mori
19th-November-2007, 12:43 PM
Thus meaning M will be 1 or 2

Although you did indeed get the correct answer, and earlier post of mine explains why M has to be 1, and there is no other even possible option.
TombStone
19th-November-2007, 01:05 PM
Edit: nvm, didn't see page two
Memento Mori
19th-November-2007, 01:19 PM
I'm on 50 posts per page, so don't have a page 2. But I'm guessing you guys are all referring to Big!'s post with the solution.
TombStone
19th-November-2007, 01:28 PM
i got 20 posts per page, and i don't even remember what i typed
debo12
19th-November-2007, 05:48 PM
dam i hate math i thought i was bouit 2 xplode.anybody seen LSD?
TombStone
19th-November-2007, 05:49 PM
He's creepin through here somewhere...